A survey determines that mint chocolate chip is the favorite ice cream flavor of 6% of consumers. An ice cream shop determines that of 190 customers, 15 customers stated their preference for mint chocolate chip. Find the P-value that would be used to determine if the percentage of customers who prefer mint chocolate chip ice has increased at a 5% level of significance. P-value:

Answer: 0.1356661Step-by-step explanation:Let p be the population proportion.By the given information, we haveNull Hypothesis: [tex]H_0: p=0.06[/tex]Alternative Hypothesis : [tex]H_1: p>0.06[/tex]Since , the alternative hypothesis is right-tailed , then the test is a right -tailed test.Given : Sample size : n= 190Number of customers stated their preference for mint chocolate chip : 15The , the sample proportion : [tex]\hat{p}=\dfrac{15}{190}\approx0.079[/tex]Test statistic for proportion: [tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}[/tex]i.e  [tex]z=\dfrac{0.079-0.06}{\sqrt{\dfrac{0.06\cdot0.94}{190}}}\approx1.10[/tex]By using the standard normal distribution table for z-score , we have P-value for right tailed test : [tex]P(Z>z)=1-P(Z<z)[/tex]i.e. [tex]P(Z>1.10)=1-P(Z<1.10)=1-0.8643339=0.1356661[/tex]