HELP (I WILL GIVE 30 POINTS) For the function f(x) = (8-2x)2 ,find f-1 . Determine whether f-1 is a function.answer choices:f-1(x) = ±8+x2−−−√; f-1 is a functionf-1(x) = ±8+x2−−−√; f-1 is not a functionf-1(x) = 8±x√2; f-1 is not a functionf-1(x) = 8±x√2; f-1 is a function
Accepted Solution
A:
Answer:4 ± 1/2sqrt(x) = yThis is not a functionStep-by-step explanation:f(x) = (8-2x)^2y = (8-2x)^2To find the inverse function, exchange x and y and then solve for yx = (8-2y)^2Take the square root of each side±sqrt(x) = 8-2ySubtract 8 from each side-8±sqrt(x) = 8-8-2y-8±sqrt(x) = -2yDivide by -2-8/-2± 1/2sqrt(x) = -2/-2y4 ± 1/2sqrt(x) = yThis is not a function