MATH SOLVE

4 months ago

Q:
# Objects A and B are in harmonic motion modeled by yA = 8 sin(2t − π/3) and yB = 8 sin(2t − π/4) The phase difference between yA and yB is ....?

Accepted Solution

A:

Answer:The phase difference between yA and yB is [tex]\frac{-\pi }{12}[/tex] Step-by-step explanation:Given harmonic modeled as :yA = 8 sin(2t - [tex]\frac{\pi }{3}[/tex]) And yB = 8 sin(2t - [tex]\frac{\pi }{4}[/tex]) The function as written as :y = a sin(ωt - Ф) where Ф is phase difference So , phase difference between yA and yB = ( Ф_1 - Ф_2 )Or phase difference between yA and yB = ( - [tex]\frac{\pi }{3}[/tex] + [tex]\frac{\pi }{4}[/tex] )Or, phase difference between yA and yB = [tex](\frac{-4\pi +3\pi }{12})[/tex]I.e phase difference between yA and yB =[tex]\frac{-\pi }{12}[/tex]Hence The phase difference between yA and yB is [tex]\frac{-\pi }{12}[/tex] Answer